Gillian had 200 coins.
25 were gold and the rest were red and silver. The ratio of the number of red coins to the number of silver coins was 1 : 4. Gillian decided to buy some more gold coins to increase the number of gold coins to half of the total number of coins.
- How many less red coins than gold coins did he have at first?
- How many more gold coins did he have to buy?
Gold coins |
Red coins |
Silver coins |
Total |
2x5 |
3x5 |
|
|
1x3 |
4x3 |
|
10 u |
3 u |
12 u |
200 |
|
Gold coins |
Red coins |
Silver coins |
Before |
10 u |
3 u |
12 u |
Change |
+ ? |
|
|
After |
15 u |
15 u |
Comparing gold, red and silver coins in the end |
1 |
1 |
(a)
The total number of red coins and silver coins is repeated. Make the total number of red coins and silver coins the same. LCM of 3 and 5 is 15.
Total number of coins at first
= 10 u + 3 u + 12 u
= 25 u
25 u = 200
1 u = 200 ÷ 25 = 8
Number of less red coins than gold coins at first
= 10 u - 3 u
= 7 u
= 7 x 8
= 56
(b)
Number of more gold coins that Gillian had to buy
= 15 u - 10 u
= 5 u
= 5 x 8
= 40
Answer(s): (a) 56; (b) 40