Pamela had 40 buttons.
25 were brown and the rest were yellow and red. The ratio of the number of yellow buttons to the number of red buttons was 1 : 3. Pamela decided to buy some more brown buttons to increase the number of brown buttons to half of the total number of buttons.
- How many less yellow buttons than brown buttons did he have at first?
- How many more brown buttons did he have to buy?
Brown buttons |
Yellow buttons |
Red buttons |
Total |
2x4 |
3x4 |
|
|
1x3 |
3x3 |
|
8 u |
3 u |
9 u |
40 |
|
Brown buttons |
Yellow buttons |
Red buttons |
Before |
8 u |
3 u |
9 u |
Change |
+ ? |
|
|
After |
12 u |
12 u |
Comparing brown, yellow and red buttons in the end |
1 |
1 |
(a)
The total number of yellow buttons and red buttons is repeated. Make the total number of yellow buttons and red buttons the same. LCM of 3 and 4 is 12.
Total number of buttons at first
= 8 u + 3 u + 9 u
= 20 u
20 u = 40
1 u = 40 ÷ 20 = 2
Number of less yellow buttons than brown buttons at first
= 8 u - 3 u
= 5 u
= 5 x 2
= 10
(b)
Number of more brown buttons that Pamela had to buy
= 12 u - 8 u
= 4 u
= 4 x 2
= 8
Answer(s): (a) 10; (b) 8