Nora had 420 stickers.
27 were green and the rest were silver and red. The ratio of the number of silver stickers to the number of red stickers was 1 : 5. Nora decided to buy some more green stickers to increase the number of green stickers to half of the total number of stickers.
- How many less silver stickers than green stickers did he have at first?
- How many more green stickers did he have to buy?
Green stickers |
Silver stickers |
Red stickers |
Total |
2x6 |
5x6 |
|
|
1x5 |
5x5 |
|
12 u |
5 u |
25 u |
420 |
|
Green stickers |
Silver stickers |
Red stickers |
Before |
12 u |
5 u |
25 u |
Change |
+ ? |
|
|
After |
30 u |
30 u |
Comparing green, silver and red stickers in the end |
1 |
1 |
(a)
The total number of silver stickers and red stickers is repeated. Make the total number of silver stickers and red stickers the same. LCM of 5 and 6 is 30.
Total number of stickers at first
= 12 u + 5 u + 25 u
= 42 u
42 u = 420
1 u = 420 ÷ 42 = 10
Number of less silver stickers than green stickers at first
= 12 u - 5 u
= 7 u
= 7 x 10
= 70
(b)
Number of more green stickers that Nora had to buy
= 30 u - 12 u
= 18 u
= 18 x 10
= 180
Answer(s): (a) 70; (b) 180