Fred had 75 beads.
45 were yellow and the rest were brown and gold. The ratio of the number of brown beads to the number of gold beads was 1 : 2. Fred decided to give away some yellow beads to decrease the number of yellow beads to half of the total number of beads.
- How many more yellow beads than brown beads did he have at first?
- How many yellow beads did he have to give away?
Yellow beads |
Brown beads |
Gold beads |
Total |
4x3 |
1x3 |
|
|
1x1 |
2x1 |
|
12 u |
1 u |
2 u |
75 |
|
Yellow beads |
Brown beads |
Gold beads |
Before |
12 u |
1 u |
2 u |
Change |
- ? |
|
|
After |
3 u |
3 u |
Comparing yellow, brown and gold beads in the end |
1 |
1 |
(a)
The total number of brown beads and gold beads is repeated. Make the total number of brown beads and gold beads the same. LCM of 1 and 3 is 3.
Total number of beads at first
= 12 u + 1 u + 2 u
= 15 u
15 u = 75
1 u = 75 ÷ 15 = 5
Number of more yellow beads than brown beads at first
= 12 u - 1 u
= 11 u
= 11 x 5
= 55
(b)
Number of more yellow beads that Fred had to give away
= 12 u - 3 u
= 9 u
= 9 x 5
= 45
Answer(s): (a) 55; (b) 45