Nicole had 80 pencils.
25 were green and the rest were grey and black. The ratio of the number of grey pencils to the number of black pencils was 1 : 3. Nicole decided to buy some more green pencils to increase the number of green pencils to half of the total number of pencils.
- How many less grey pencils than green pencils did he have at first?
- How many more green pencils did he have to buy?
Green pencils |
Grey pencils |
Black pencils |
Total |
2x4 |
3x4 |
|
|
1x3 |
3x3 |
|
8 u |
3 u |
9 u |
80 |
|
Green pencils |
Grey pencils |
Black pencils |
Before |
8 u |
3 u |
9 u |
Change |
+ ? |
|
|
After |
12 u |
12 u |
Comparing green, grey and black pencils in the end |
1 |
1 |
(a)
The total number of grey pencils and black pencils is repeated. Make the total number of grey pencils and black pencils the same. LCM of 3 and 4 is 12.
Total number of pencils at first
= 8 u + 3 u + 9 u
= 20 u
20 u = 80
1 u = 80 ÷ 20 = 4
Number of less grey pencils than green pencils at first
= 8 u - 3 u
= 5 u
= 5 x 4
= 20
(b)
Number of more green pencils that Nicole had to buy
= 12 u - 8 u
= 4 u
= 4 x 4
= 16
Answer(s): (a) 20; (b) 16