Tim had 140 erasers.
34 were brown and the rest were grey and gold. The ratio of the number of grey erasers to the number of gold erasers was 1 : 4. Tim decided to give away some brown erasers to decrease the number of brown erasers to half of the total number of erasers.
- How many more brown erasers than grey erasers did he have at first?
- How many brown erasers did he have to give away?
Brown erasers |
Grey erasers |
Gold erasers |
Total |
3x5 |
1x5 |
|
|
1x1 |
4x1 |
|
15 u |
1 u |
4 u |
140 |
|
Brown erasers |
Grey erasers |
Gold erasers |
Before |
15 u |
1 u |
4 u |
Change |
- ? |
|
|
After |
5 u |
5 u |
Comparing brown, grey and gold erasers in the end |
1 |
1 |
(a)
The total number of grey erasers and gold erasers is repeated. Make the total number of grey erasers and gold erasers the same. LCM of 1 and 5 is 5.
Total number of erasers at first
= 15 u + 1 u + 4 u
= 20 u
20 u = 140
1 u = 140 ÷ 20 = 7
Number of more brown erasers than grey erasers at first
= 15 u - 1 u
= 14 u
= 14 x 7
= 98
(b)
Number of more brown erasers that Tim had to give away
= 15 u - 5 u
= 10 u
= 10 x 7
= 70
Answer(s): (a) 98; (b) 70