Zeph had 216 coins.
56 were black and the rest were silver and purple. The ratio of the number of silver coins to the number of purple coins was 1 : 5. Zeph decided to give away some black coins to decrease the number of black coins to half of the total number of coins.
- How many more black coins than silver coins did he have at first?
- How many black coins did he have to give away?
Black coins |
Silver coins |
Purple coins |
Total |
5x6 |
1x6 |
|
|
1x1 |
5x1 |
|
30 u |
1 u |
5 u |
216 |
|
Black coins |
Silver coins |
Purple coins |
Before |
30 u |
1 u |
5 u |
Change |
- ? |
|
|
After |
6 u |
6 u |
Comparing black, silver and purple coins in the end |
1 |
1 |
(a)
The total number of silver coins and purple coins is repeated. Make the total number of silver coins and purple coins the same. LCM of 1 and 6 is 6.
Total number of coins at first
= 30 u + 1 u + 5 u
= 36 u
36 u = 216
1 u = 216 ÷ 36 = 6
Number of more black coins than silver coins at first
= 30 u - 1 u
= 29 u
= 29 x 6
= 174
(b)
Number of more black coins that Zeph had to give away
= 30 u - 6 u
= 24 u
= 24 x 6
= 144
Answer(s): (a) 174; (b) 144