Lynn had 84 coins.
27 were black and the rest were green and gold. The ratio of the number of green coins to the number of gold coins was 1 : 5. Lynn decided to buy some more black coins to increase the number of black coins to half of the total number of coins.
- How many less green coins than black coins did he have at first?
- How many more black coins did he have to buy?
Black coins |
Green coins |
Gold coins |
Total |
2x6 |
5x6 |
|
|
1x5 |
5x5 |
|
12 u |
5 u |
25 u |
84 |
|
Black coins |
Green coins |
Gold coins |
Before |
12 u |
5 u |
25 u |
Change |
+ ? |
|
|
After |
30 u |
30 u |
Comparing black, green and gold coins in the end |
1 |
1 |
(a)
The total number of green coins and gold coins is repeated. Make the total number of green coins and gold coins the same. LCM of 5 and 6 is 30.
Total number of coins at first
= 12 u + 5 u + 25 u
= 42 u
42 u = 84
1 u = 84 ÷ 42 = 2
Number of less green coins than black coins at first
= 12 u - 5 u
= 7 u
= 7 x 2
= 14
(b)
Number of more black coins that Lynn had to buy
= 30 u - 12 u
= 18 u
= 18 x 2
= 36
Answer(s): (a) 14; (b) 36