The total number of balls in Basket W, Basket X and Basket Y was 132. ²₇ of the balls from Basket W and 33 balls from Basket X were removed. More balls were then added into Basket Y until the number of balls in it was doubled. The ratio of the number of balls in Basket W to Basket X to Basket Y became 5 : 3 : 2.

1. How many less balls were there in Basket X than Basket W at first?
2. Find the total number of balls in Basket X and Basket Y in the end.

	Basket W	Basket X	Basket Y	Total
Before	7 u	3 u + 33	1 u	132
Change	- 2 u	- 33	+ 1 u
After	5 u		2 u
Comparing the balls  in the end	5 u	3 u	2 u

(a)
Total number of balls at first
= 7 u + 3 u + 33 + 1 u
= 11 u + 33

11 u + 33 = 132
11 u = 132 - 33
11 u = 99

1 u = 99 ÷ 11 = 9

Number of less balls in Basket X than Basket W at first 
= 7 u - (3 u + 33)
= 7 u - 3 u - 33
= 4 u - 33
= 4 x 9 - 33
= 36 - 33
= 3

(b)
Total number of balls in Basket X and Basket Y in the end
= 3 u + 2 u
= 5 u
= 5 x 9
= 45 

Answer(s): (a) 3; (b) 45