The total number of marbles in Basket H, Basket J and Basket K was 136.
37 of the marbles from Basket H and 16 marbles from Basket J were removed. More marbles were then added into Basket K until the number of marbles in it was tripled. The ratio of the number of marbles in Basket H to Basket J to Basket K became 4 : 2 : 3.
- How many less marbles were there in Basket J than Basket H at first?
- Find the total number of marbles in Basket J and Basket K in the end.
|
Basket H |
Basket J |
Basket K |
Total |
Before |
7 u |
2 u + 16 |
1 u |
136 |
Change |
- 3 u |
- 16 |
+ 2 u |
|
After |
4 u |
|
3 u |
|
Comparing the marbles in the end |
4 u |
2 u |
3 u |
|
(a)
Total number of marbles at first
= 7 u + 2 u + 16 + 1 u
= 10 u + 16
10 u + 16 = 136
10 u = 136 - 16
10 u = 120
1 u = 120 ÷ 10 = 12
Number of less marbles in Basket J than Basket H at first
= 7 u - (2 u + 16)
= 7 u - 2 u - 16
= 5 u - 16
= 5 x 12 - 16
= 60 - 16
= 44
(b)
Total number of marbles in Basket J and Basket K in the end
= 2 u + 3 u
= 5 u
= 5 x 12
= 60
Answer(s): (a) 44; (b) 60