The total number of marbles in Basket C, Basket D and Basket E was 94. ⁴₅ of the marbles from Basket C and 14 marbles from Basket D were removed. More marbles were then added into Basket E until the number of marbles in it was tripled. The ratio of the number of marbles in Basket C to Basket D to Basket E became 1 : 2 : 3.

1. How many less marbles were there in Basket D than Basket C at first?
2. Find the total number of marbles in Basket D and Basket E in the end.

	Basket C	Basket D	Basket E	Total
Before	5 u	2 u + 14	1 u	94
Change	- 4 u	- 14	+ 2 u
After	1 u		3 u
Comparing the marbles  in the end	1 u	2 u	3 u

(a)
Total number of marbles at first
= 5 u + 2 u + 14 + 1 u
= 8 u + 14

8 u + 14 = 94
8 u = 94 - 14
8 u = 80

1 u = 80 ÷ 8 = 10

Number of less marbles in Basket D than Basket C at first 
= 5 u - (2 u + 14)
= 5 u - 2 u - 14
= 3 u - 14
= 3 x 10 - 14
= 30 - 14
= 16

(b)
Total number of marbles in Basket D and Basket E in the end
= 2 u + 3 u
= 5 u
= 5 x 10
= 50 

Answer(s): (a) 16; (b) 50