The total number of balls in Basket T, Basket U and Basket V was 125. ³₅ of the balls from Basket T and 17 balls from Basket U were removed. More balls were then added into Basket V until the number of balls in it was quadrupled. The ratio of the number of balls in Basket T to Basket U to Basket V became 2 : 3 : 4.

1. How many less balls were there in Basket U than Basket T at first?
2. Find the total number of balls in Basket U and Basket V in the end.

	Basket T	Basket U	Basket V	Total
Before	5 u	3 u + 17	1 u	125
Change	- 3 u	- 17	+ 3 u
After	2 u		4 u
Comparing the balls  in the end	2 u	3 u	4 u

(a)
Total number of balls at first
= 5 u + 3 u + 17 + 1 u
= 9 u + 17

9 u + 17 = 125
9 u = 125 - 17
9 u = 108

1 u = 108 ÷ 9 = 12

Number of less balls in Basket U than Basket T at first 
= 5 u - (3 u + 17)
= 5 u - 3 u - 17
= 2 u - 17
= 2 x 12 - 17
= 24 - 17
= 7

(b)
Total number of balls in Basket U and Basket V in the end
= 3 u + 4 u
= 7 u
= 7 x 12
= 84 

Answer(s): (a) 7; (b) 84