The total number of marbles in Basket X, Basket Y and Basket Z was 72.
58 of the marbles from Basket X and 6 marbles from Basket Y were removed. More marbles were then added into Basket Z until the number of marbles in it was doubled. The ratio of the number of marbles in Basket X to Basket Y to Basket Z became 3 : 2 : 2.
- How many less marbles were there in Basket Y than Basket X at first?
- Find the total number of marbles in Basket Y and Basket Z in the end.
|
Basket X |
Basket Y |
Basket Z |
Total |
Before |
8 u |
2 u + 6 |
1 u |
72 |
Change |
- 5 u |
- 6 |
+ 1 u |
|
After |
3 u |
|
2 u |
|
Comparing the marbles in the end |
3 u |
2 u |
2 u |
|
(a)
Total number of marbles at first
= 8 u + 2 u + 6 + 1 u
= 11 u + 6
11 u + 6 = 72
11 u = 72 - 6
11 u = 66
1 u = 66 ÷ 11 = 6
Number of less marbles in Basket Y than Basket X at first
= 8 u - (2 u + 6)
= 8 u - 2 u - 6
= 6 u - 6
= 6 x 6 - 6
= 36 - 6
= 30
(b)
Total number of marbles in Basket Y and Basket Z in the end
= 2 u + 2 u
= 4 u
= 4 x 6
= 24
Answer(s): (a) 30; (b) 24