The total number of balls in Basket L, Basket M and Basket N was 164. ⁵₈ of the balls from Basket L and 34 balls from Basket M were removed. More balls were then added into Basket N until the number of balls in it was doubled. The ratio of the number of balls in Basket L to Basket M to Basket N became 3 : 4 : 2.

1. How many more balls were there in Basket L than Basket M at first?
2. Find the total number of balls in Basket L and Basket N in the end.

	Basket L	Basket M	Basket N	Total
Before	8 u	4 u + 34	1 u	164
Change	- 5 u	- 34	+ 1 u
After	3 u		2 u
Comparing the balls  in the end	3 u	4 u	2 u

(a)
Total number of balls at first
= 8 u + 4 u + 34 + 1 u
= 13 u + 34

13 u + 34 = 164
13 u = 164 - 34
13 u = 130

1 u = 130 ÷ 13 = 10

Number of more balls in Basket L than Basket M at first 
= 8 u - (4 u + 34)
= 8 u - 4 u - 34
= 4 u - 34
= 4 x 10 - 34
= 40 - 34
= 6

(b)
Total number of balls in Basket L and Basket N in the end
= 3 u + 2 u
= 5 u
= 5 x 10
= 50 

Answer(s): (a) 6; (b) 50