The total number of balls in Basket U, Basket V and Basket W was 118. ³₇ of the balls from Basket U and 22 balls from Basket V were removed. More balls were then added into Basket W until the number of balls in it was tripled. The ratio of the number of balls in Basket U to Basket V to Basket W became 4 : 4 : 3.

1. How many less balls were there in Basket V than Basket U at first?
2. Find the total number of balls in Basket V and Basket W in the end.

	Basket U	Basket V	Basket W	Total
Before	7 u	4 u + 22	1 u	118
Change	- 3 u	- 22	+ 2 u
After	4 u		3 u
Comparing the balls  in the end	4 u	4 u	3 u

(a)
Total number of balls at first
= 7 u + 4 u + 22 + 1 u
= 12 u + 22

12 u + 22 = 118
12 u = 118 - 22
12 u = 96

1 u = 96 ÷ 12 = 8

Number of less balls in Basket V than Basket U at first 
= 7 u - (4 u + 22)
= 7 u - 4 u - 22
= 3 u - 22
= 3 x 8 - 22
= 24 - 22
= 2

(b)
Total number of balls in Basket V and Basket W in the end
= 4 u + 3 u
= 7 u
= 7 x 8
= 56 

Answer(s): (a) 2; (b) 56