The total number of beads in Basket H, Basket J and Basket K was 147. ³₈ of the beads from Basket H and 26 beads from Basket J were removed. More beads were then added into Basket K until the number of beads in it was tripled. The ratio of the number of beads in Basket H to Basket J to Basket K became 5 : 2 : 3.

1. How many less beads were there in Basket J than Basket H at first?
2. Find the total number of beads in Basket J and Basket K in the end.

	Basket H	Basket J	Basket K	Total
Before	8 u	2 u + 26	1 u	147
Change	- 3 u	- 26	+ 2 u
After	5 u		3 u
Comparing the beads  in the end	5 u	2 u	3 u

(a)
Total number of beads at first
= 8 u + 2 u + 26 + 1 u
= 11 u + 26

11 u + 26 = 147
11 u = 147 - 26
11 u = 121

1 u = 121 ÷ 11 = 11

Number of less beads in Basket J than Basket H at first 
= 8 u - (2 u + 26)
= 8 u - 2 u - 26
= 6 u - 26
= 6 x 11 - 26
= 66 - 26
= 40

(b)
Total number of beads in Basket J and Basket K in the end
= 2 u + 3 u
= 5 u
= 5 x 11
= 55 

Answer(s): (a) 40; (b) 55