The total number of marbles in Basket L, Basket M and Basket N was 193. ³₈ of the marbles from Basket L and 25 marbles from Basket M were removed. More marbles were then added into Basket N until the number of marbles in it was doubled. The ratio of the number of marbles in Basket L to Basket M to Basket N became 5 : 5 : 2.

1. How many less marbles were there in Basket M than Basket L at first?
2. Find the total number of marbles in Basket M and Basket N in the end.

	Basket L	Basket M	Basket N	Total
Before	8 u	5 u + 25	1 u	193
Change	- 3 u	- 25	+ 1 u
After	5 u		2 u
Comparing the marbles  in the end	5 u	5 u	2 u

(a)
Total number of marbles at first
= 8 u + 5 u + 25 + 1 u
= 14 u + 25

14 u + 25 = 193
14 u = 193 - 25
14 u = 168

1 u = 168 ÷ 14 = 12

Number of less marbles in Basket M than Basket L at first 
= 8 u - (5 u + 25)
= 8 u - 5 u - 25
= 3 u - 25
= 3 x 12 - 25
= 36 - 25
= 11

(b)
Total number of marbles in Basket M and Basket N in the end
= 5 u + 2 u
= 7 u
= 7 x 12
= 84 

Answer(s): (a) 11; (b) 84