Robert had 25% more cards than Levi. Tommy had 50% fewer cards than Robert. Robert and Levi gave Tommy some cards in the ratio of 4 : 5. As a result, Tommy had 60% more cards than before. Given that Levi had 45 less cards than Tommy in the end, how many cards did Levi give to Tommy?
Robert |
Levi |
Tommy |
5x2 |
4x2 |
|
2x5 |
|
1x5 |
10 |
8 |
5 |
100% + 25% = 125%
125% =
125100 =
54Robert : Levi = 5 : 4
100% - 50% = 50%
50% =
50100 =
12 Robert : Tommy = 2 : 1
The number of cards that Robert had at first is repeated. Make the number of cards that Robert had at first the same. LCM of 5 and 2 is 10.
|
Robert |
Levi |
Tommy |
Before |
10x3 = 30 u |
8x3 = 24 u |
5x3 = 15 u |
Change |
|
|
+ 3x3 = + 9 u |
Comparing the changes in the number of cards |
- 4x1 = - 4 u |
- 5x1 = - 5 u |
+ 9x1 = + 9 u |
After |
26 u |
19 u |
8x3 = 24 u |
60% x 5
=
60100 x 5
= 3
The total number of cards that Robert and Levi gave to Tommy is repeated. Make the total number of cards that Robert and Levi gave to Tommy the same. LCM of 9 and 3 is 9.
Number of cards that Levi had less than Tommy
= 24 u - 19 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of cards that Levi gave to Tommy
= 5 u
= 5 x 9
= 45
Answer(s): 45