Luke had 50% more coins than Mason. Henry had 20% fewer coins than Luke. Luke and Mason gave Henry some coins in the ratio of 4 : 5. As a result, Henry had 50% more coins than before. Given that Henry had 204 more coins than Mason in the end, how many coins did Luke give to Henry?
Luke |
Mason |
Henry |
3x5 |
2x5 |
|
5x3 |
|
4x3 |
15 |
10 |
12 |
100% + 50% = 150%
150% =
150100 =
32Luke : Mason = 3 : 2
100% - 20% = 80%
80% =
80100 =
45 Luke : Henry = 5 : 4
The number of coins that Luke had at first is repeated. Make the number of coins that Luke had at first the same. LCM of 3 and 5 is 15.
|
Luke |
Mason |
Henry |
Before |
15x3 = 45 u |
10x3 = 30 u |
12x3 = 36 u |
Change |
|
|
+ 6x3 = + 18 u |
Comparing the changes in the number of coins |
- 4x2 = - 8 u |
- 5x2 = - 10 u |
+ 9x2 = + 18 u |
After |
37 u |
20 u |
18x3 = 54 u |
50% x 12
=
50100 x 12
= 6
The total number of coins that Luke and Mason gave to Henry is repeated. Make the total number of coins that Luke and Mason gave to Henry the same. LCM of 9 and 6 is 18.
Number of coins that Henry had more than Mason
= 54 u - 20 u
= 34 u
34 u = 204
1 u = 204 ÷ 34 = 6
Number of coins that Luke gave to Henry
= 8 u
= 8 x 6
= 48
Answer(s): 48