Owen had 25% more coins than Isabella. Chloe had 50% fewer coins than Owen. Owen and Isabella gave Chloe some coins in the ratio of 1 : 3. As a result, Chloe had 60% more coins than before. Given that Isabella had 54 less coins than Chloe in the end, how many coins did Isabella give to Chloe?
Owen |
Isabella |
Chloe |
5x2 |
4x2 |
|
2x5 |
|
1x5 |
10 |
8 |
5 |
100% + 25% = 125%
125% =
125100 =
54Owen : Isabella = 5 : 4
100% - 50% = 50%
50% =
50100 =
12 Owen : Chloe = 2 : 1
The number of coins that Owen had at first is repeated. Make the number of coins that Owen had at first the same. LCM of 5 and 2 is 10.
|
Owen |
Isabella |
Chloe |
Before |
10x4 = 40 u |
8x4 = 32 u |
5x4 = 20 u |
Change |
|
|
+ 3x4 = + 12 u |
Comparing the changes in the number of coins |
- 1x3 = - 3 u |
- 3x3 = - 9 u |
+ 4x3 = + 12 u |
After |
37 u |
23 u |
8x4 = 32 u |
60% x 5
=
60100 x 5
= 3
The total number of coins that Owen and Isabella gave to Chloe is repeated. Make the total number of coins that Owen and Isabella gave to Chloe the same. LCM of 4 and 3 is 12.
Number of coins that Isabella had less than Chloe
= 32 u - 23 u
= 9 u
9 u = 54
1 u = 54 ÷ 9 = 6
Number of coins that Isabella gave to Chloe
= 9 u
= 9 x 6
= 54
Answer(s): 54