Julie had 25% more marbles than Victoria. Josiah had 50% fewer marbles than Julie. Julie and Victoria gave Josiah some marbles in the ratio of 1 : 5. As a result, Josiah had 60% more marbles than before. Given that Victoria had 30 less marbles than Josiah in the end, how many marbles did Victoria give to Josiah?
Julie |
Victoria |
Josiah |
5x2 |
4x2 |
|
2x5 |
|
1x5 |
10 |
8 |
5 |
100% + 25% = 125%
125% =
125100 =
54Julie : Victoria = 5 : 4
100% - 50% = 50%
50% =
50100 =
12 Julie : Josiah = 2 : 1
The number of marbles that Julie had at first is repeated. Make the number of marbles that Julie had at first the same. LCM of 5 and 2 is 10.
|
Julie |
Victoria |
Josiah |
Before |
10x2 = 20 u |
8x2 = 16 u |
5x2 = 10 u |
Change |
|
|
+ 3x2 = + 6 u |
Comparing the changes in the number of marbles |
- 1x1 = - 1 u |
- 5x1 = - 5 u |
+ 6x1 = + 6 u |
After |
19 u |
11 u |
8x2 = 16 u |
60% x 5
=
60100 x 5
= 3
The total number of marbles that Julie and Victoria gave to Josiah is repeated. Make the total number of marbles that Julie and Victoria gave to Josiah the same. LCM of 6 and 3 is 6.
Number of marbles that Victoria had less than Josiah
= 16 u - 11 u
= 5 u
5 u = 30
1 u = 30 ÷ 5 = 6
Number of marbles that Victoria gave to Josiah
= 5 u
= 5 x 6
= 30
Answer(s): 30