Kaylee had 25% more pens than Isaiah. Anna had 50% fewer pens than Kaylee. Kaylee and Isaiah gave Anna some pens in the ratio of 3 : 5. As a result, Anna had 60% more pens than before. Given that Isaiah had 90 less pens than Anna in the end, how many pens did Isaiah give to Anna?
Kaylee |
Isaiah |
Anna |
5x2 |
4x2 |
|
2x5 |
|
1x5 |
10 |
8 |
5 |
100% + 25% = 125%
125% =
125100 =
54Kaylee : Isaiah = 5 : 4
100% - 50% = 50%
50% =
50100 =
12 Kaylee : Anna = 2 : 1
The number of pens that Kaylee had at first is repeated. Make the number of pens that Kaylee had at first the same. LCM of 5 and 2 is 10.
|
Kaylee |
Isaiah |
Anna |
Before |
10x8 = 80 u |
8x8 = 64 u |
5x8 = 40 u |
Change |
|
|
+ 3x8 = + 24 u |
Comparing the changes in the number of pens |
- 3x3 = - 9 u |
- 5x3 = - 15 u |
+ 8x3 = + 24 u |
After |
71 u |
49 u |
8x8 = 64 u |
60% x 5
=
60100 x 5
= 3
The total number of pens that Kaylee and Isaiah gave to Anna is repeated. Make the total number of pens that Kaylee and Isaiah gave to Anna the same. LCM of 8 and 3 is 24.
Number of pens that Isaiah had less than Anna
= 64 u - 49 u
= 15 u
15 u = 90
1 u = 90 ÷ 15 = 6
Number of pens that Isaiah gave to Anna
= 15 u
= 15 x 6
= 90
Answer(s): 90