David had 50% more stickers than Jackson. Lilian had 20% fewer stickers than David. David and Jackson gave Lilian some stickers in the ratio of 4 : 5. As a result, Lilian had 25% more stickers than before. Given that Lilian had 200 more stickers than Jackson in the end, how many stickers did David give to Lilian?
David |
Jackson |
Lilian |
3x5 |
2x5 |
|
5x3 |
|
4x3 |
15 |
10 |
12 |
100% + 50% = 150%
150% =
150100 =
32David : Jackson = 3 : 2
100% - 20% = 80%
80% =
80100 =
45 David : Lilian = 5 : 4
The number of stickers that David had at first is repeated. Make the number of stickers that David had at first the same. LCM of 3 and 5 is 15.
|
David |
Jackson |
Lilian |
Before |
15x3 = 45 u |
10x3 = 30 u |
12x3 = 36 u |
Change |
|
|
+ 3x3 = + 9 u |
Comparing the changes in the number of stickers |
- 4x1 = - 4 u |
- 5x1 = - 5 u |
+ 9x1 = + 9 u |
After |
41 u |
25 u |
15x3 = 45 u |
25% x 12
=
25100 x 12
= 3
The total number of stickers that David and Jackson gave to Lilian is repeated. Make the total number of stickers that David and Jackson gave to Lilian the same. LCM of 9 and 3 is 9.
Number of stickers that Lilian had more than Jackson
= 45 u - 25 u
= 20 u
20 u = 200
1 u = 200 ÷ 20 = 10
Number of stickers that David gave to Lilian
= 4 u
= 4 x 10
= 40
Answer(s): 40