A container contains some oranges, pears and apples. 0.2 of the oranges is equal to 80% of the pears. The number of apples is ¹₂ of the total number of pears and oranges. If there are 18 less pears than apples, how many fruits are there in the container altogether?

Oranges	Pears	Apples
4x2	1x2
2x5		1x5
8 u	2 u	5 u

0.2 = ²₁₀= ¹₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.2 of the oranges is equal to 80% of the pears. Make the numerators the same.  LCM of 1 and 4 is 4.

1x45x4 of the oranges = 4x15x1 of the pears
420 of the oranges = 45 of the pears 

Oranges : Pears
20 : 5 _(÷5)
4 : 1

The total number of oranges and pears is repeated.  Make the total number of oranges and pears the same.  LCM of 5 and 2 is 10.

Number of less pears than apples
= 5 u - 2 u
= 3 u

3 u = 18

1 u = 18 ÷ 3 = 6

Number of the fruits in the container altogether
= 8 u + 2 u + 5 u
= 15 u
= 15 x 6
= 90

Answer(s): 90