A box contains some kiwis, pomegranates and oranges. 0.4 of the kiwis is equal to 60% of the pomegranates. The number of oranges is ³₄ of the total number of pomegranates and kiwis. If there are 28 more oranges than pomegranates, how many fruits are there in the box altogether?

Kiwis	Pomegranates	Oranges
3x4	2x4
4x5		3x5
12 u	8 u	15 u

0.4 = ⁴₁₀= ²₅
60% = ⁶⁰₁₀₀ = ³₅

0.4 of the kiwis is equal to 60% of the pomegranates. Make the numerators the same.  LCM of 2 and 3 is 6.

2x35x3 of the kiwis = 3x25x2 of the pomegranates
615 of the kiwis = 610 of the pomegranates 

Kiwis : Pomegranates
15 : 10 _(÷5)
3 : 2

The total number of kiwis and pomegranates is repeated.  Make the total number of kiwis and pomegranates the same.  LCM of 5 and 4 is 20.

Number of more oranges than pomegranates
= 15 u - 8 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of the fruits in the box altogether
= 12 u + 8 u + 15 u
= 35 u
= 35 x 4
= 140

Answer(s): 140