A container contains some pomegranates, oranges and chikoos. 0.6 of the pomegranates is equal to 80% of the oranges. The number of chikoos is ⁴₅ of the total number of oranges and pomegranates. If there are 91 less oranges than chikoos, how many fruits are there in the container altogether?

Pomegranates	Oranges	Chikoos
4x5	3x5
5x7		4x7
20 u	15 u	28 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the pomegranates is equal to 80% of the oranges. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the pomegranates = 4x35x3 of the oranges
1220 of the pomegranates = 1215 of the oranges 

Pomegranates : Oranges
20 : 15 _(÷5)
4 : 3

The total number of pomegranates and oranges is repeated.  Make the total number of pomegranates and oranges the same.  LCM of 7 and 5 is 35.

Number of less oranges than chikoos
= 28 u - 15 u
= 13 u

13 u = 91

1 u = 91 ÷ 13 = 7

Number of the fruits in the container altogether
= 20 u + 15 u + 28 u
= 63 u
= 63 x 7
= 441

Answer(s): 441