A container contains some pears, apples and persimmons. 0.4 of the pears is equal to 70% of the apples. The number of persimmons is ²₃ of the total number of apples and pears. If there are 20 more persimmons than apples, how many fruits are there in the container altogether?

Pears	Apples	Persimmons
7x3	4x3
3x11		2x11
21 u	12 u	22 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the pears is equal to 70% of the apples. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the pears = 7x210x2 of the apples
1435 of the pears = 1420 of the apples 

Pears : Apples
35 : 20 _(÷5)
7 : 4

The total number of pears and apples is repeated.  Make the total number of pears and apples the same.  LCM of 11 and 3 is 33.

Number of more persimmons than apples
= 22 u - 12 u
= 10 u

10 u = 20

1 u = 20 ÷ 10 = 2

Number of the fruits in the container altogether
= 21 u + 12 u + 22 u
= 55 u
= 55 x 2
= 110

Answer(s): 110