A container contains some apples, kiwis and mangosteens. 0.4 of the apples is equal to 70% of the kiwis. The number of mangosteens is
45 of the total number of kiwis and apples. If there are 264 less kiwis than mangosteens, how many fruits are there in the container altogether?
Apples |
Kiwis |
Mangosteens |
7x5 |
4x5 |
|
5x11 |
4x11 |
35 u |
20 u |
44 u |
0.4 =
410=
25 70% =
70100 =
710 0.4 of the apples is equal to 70% of the kiwis. Make the numerators the same. LCM of 2 and 7 is 14.
2x75x7 of the apples =
7x210x2 of the kiwis
1435 of the apples =
1420 of the kiwis
Apples : Kiwis
35 : 20
(÷5)
7 : 4
The total number of apples and kiwis is repeated. Make the total number of apples and kiwis the same. LCM of 11 and 5 is 55.
Number of less kiwis than mangosteens
= 44 u - 20 u
= 24 u
24 u = 264
1 u = 264 ÷ 24 = 11
Number of the fruits in the container altogether
= 35 u + 20 u + 44 u
= 99 u
= 99 x 11
= 1089
Answer(s): 1089