A container contains some mangoes, pears and mangosteens. 0.2 of the mangoes is equal to 40% of the pears. The number of mangosteens is ⁵₇ of the total number of pears and mangoes. If there are 96 more mangosteens than pears, how many fruits are there in the container altogether?

Mangoes	Pears	Mangosteens
2x7	1x7
7x3		5x3
14 u	7 u	15 u

0.2 = ²₁₀= ¹₅
40% = ⁴⁰₁₀₀ = ²₅

0.2 of the mangoes is equal to 40% of the pears. Make the numerators the same.  LCM of 1 and 2 is 2.

1x25x2 of the mangoes = 2x15x1 of the pears
210 of the mangoes = 25 of the pears 

Mangoes : Pears
10 : 5 _(÷5)
2 : 1

The total number of mangoes and pears is repeated.  Make the total number of mangoes and pears the same.  LCM of 3 and 7 is 21.

Number of more mangosteens than pears
= 15 u - 7 u
= 8 u

8 u = 96

1 u = 96 ÷ 8 = 12

Number of the fruits in the container altogether
= 14 u + 7 u + 15 u
= 36 u
= 36 x 12
= 432

Answer(s): 432