A box contains some pomegranates, kiwis and lemons. 0.2 of the pomegranates is equal to 30% of the kiwis. The number of lemons is
34 of the total number of kiwis and pomegranates. If there are 28 less kiwis than lemons, how many fruits are there in the box altogether?
Pomegranates |
Kiwis |
Lemons |
3x4 |
2x4 |
|
4x5 |
3x5 |
12 u |
8 u |
15 u |
0.2 =
210=
15 30% =
30100 =
310 0.2 of the pomegranates is equal to 30% of the kiwis. Make the numerators the same. LCM of 1 and 3 is 3.
1x35x3 of the pomegranates =
3x110x1 of the kiwis
315 of the pomegranates =
310 of the kiwis
Pomegranates : Kiwis
15 : 10
(÷5)
3 : 2
The total number of pomegranates and kiwis is repeated. Make the total number of pomegranates and kiwis the same. LCM of 5 and 4 is 20.
Number of less kiwis than lemons
= 15 u - 8 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
Number of the fruits in the box altogether
= 12 u + 8 u + 15 u
= 35 u
= 35 x 4
= 140
Answer(s): 140