A container contains some starfruits, pears and persimmons. 0.8 of the starfruits is equal to 70% of the pears. The number of persimmons is
23 of the total number of pears and starfruits. If there are 6 more persimmons than pears, how many fruits are there in the container altogether?
Starfruits |
Pears |
Persimmons |
7x1 |
8x1 |
|
3x5 |
2x5 |
7 u |
8 u |
10 u |
0.8 =
810=
45 70% =
70100 =
710 0.8 of the starfruits is equal to 70% of the pears. Make the numerators the same. LCM of 4 and 7 is 28.
4x75x7 of the starfruits =
7x410x4 of the pears
2835 of the starfruits =
2840 of the pears
Starfruits : Pears
35 : 40
(÷5)
7 : 8
The total number of starfruits and pears is repeated. Make the total number of starfruits and pears the same. LCM of 15 and 3 is 15.
Number of more persimmons than pears
= 10 u - 8 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Number of the fruits in the container altogether
= 7 u + 8 u + 10 u
= 25 u
= 25 x 3
= 75
Answer(s): 75