A container contains some chikoos, pomegranates and lemons. 0.2 of the chikoos is equal to 80% of the pomegranates. The number of lemons is
34 of the total number of pomegranates and chikoos. If there are 121 more lemons than pomegranates, how many fruits are there in the container altogether?
Chikoos |
Pomegranates |
Lemons |
4x4 |
1x4 |
|
4x5 |
3x5 |
16 u |
4 u |
15 u |
0.2 =
210=
15 80% =
80100 =
45 0.2 of the chikoos is equal to 80% of the pomegranates. Make the numerators the same. LCM of 1 and 4 is 4.
1x45x4 of the chikoos =
4x15x1 of the pomegranates
420 of the chikoos =
45 of the pomegranates
Chikoos : Pomegranates
20 : 5
(÷5)
4 : 1
The total number of chikoos and pomegranates is repeated. Make the total number of chikoos and pomegranates the same. LCM of 5 and 4 is 20.
Number of more lemons than pomegranates
= 15 u - 4 u
= 11 u
11 u = 121
1 u = 121 ÷ 11 = 11
Number of the fruits in the container altogether
= 16 u + 4 u + 15 u
= 35 u
= 35 x 11
= 385
Answer(s): 385