A container contains some oranges, kiwis and lemons. 0.4 of the oranges is equal to 70% of the kiwis. The number of lemons is ²₃ of the total number of kiwis and oranges. If there are 70 more lemons than kiwis, how many fruits are there in the container altogether?

Oranges	Kiwis	Lemons
7x3	4x3
3x11		2x11
21 u	12 u	22 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the oranges is equal to 70% of the kiwis. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the oranges = 7x210x2 of the kiwis
1435 of the oranges = 1420 of the kiwis 

Oranges : Kiwis
35 : 20 _(÷5)
7 : 4

The total number of oranges and kiwis is repeated.  Make the total number of oranges and kiwis the same.  LCM of 11 and 3 is 33.

Number of more lemons than kiwis
= 22 u - 12 u
= 10 u

10 u = 70

1 u = 70 ÷ 10 = 7

Number of the fruits in the container altogether
= 21 u + 12 u + 22 u
= 55 u
= 55 x 7
= 385

Answer(s): 385