A box contains some mangoes, pears and kiwis. 0.4 of the mangoes is equal to 80% of the pears. The number of kiwis is ⁵₇ of the total number of pears and mangoes. If there are 48 more kiwis than pears, how many fruits are there in the box altogether?

Mangoes	Pears	Kiwis
2x7	1x7
7x3		5x3
14 u	7 u	15 u

0.4 = ⁴₁₀= ²₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.4 of the mangoes is equal to 80% of the pears. Make the numerators the same.  LCM of 2 and 4 is 4.

2x25x2 of the mangoes = 4x15x1 of the pears
410 of the mangoes = 45 of the pears 

Mangoes : Pears
10 : 5 _(÷5)
2 : 1

The total number of mangoes and pears is repeated.  Make the total number of mangoes and pears the same.  LCM of 3 and 7 is 21.

Number of more kiwis than pears
= 15 u - 7 u
= 8 u

8 u = 48

1 u = 48 ÷ 8 = 6

Number of the fruits in the box altogether
= 14 u + 7 u + 15 u
= 36 u
= 36 x 6
= 216

Answer(s): 216