A container contains some oranges, pears and lemons. 0.8 of the oranges is equal to 60% of the pears. The number of lemons is ⁵₈ of the total number of pears and oranges. If there are 27 less pears than lemons, how many fruits are there in the container altogether?

Oranges	Pears	Lemons
3x8	4x8
8x7		5x7
24 u	32 u	35 u

0.8 = ⁸₁₀= ⁴₅
60% = ⁶⁰₁₀₀ = ³₅

0.8 of the oranges is equal to 60% of the pears. Make the numerators the same.  LCM of 4 and 3 is 12.

4x35x3 of the oranges = 3x45x4 of the pears
1215 of the oranges = 1220 of the pears 

Oranges : Pears
15 : 20 _(÷5)
3 : 4

The total number of oranges and pears is repeated.  Make the total number of oranges and pears the same.  LCM of 7 and 8 is 56.

Number of less pears than lemons
= 35 u - 32 u
= 3 u

3 u = 27

1 u = 27 ÷ 3 = 9

Number of the fruits in the container altogether
= 24 u + 32 u + 35 u
= 91 u
= 91 x 9
= 819

Answer(s): 819