A box contains some persimmons, apples and pomegranates. 0.2 of the persimmons is equal to 70% of the apples. The number of pomegranates is ³₄ of the total number of apples and persimmons. If there are 76 less apples than pomegranates, how many fruits are there in the box altogether?

Persimmons	Apples	Pomegranates
7x4	2x4
4x9		3x9
28 u	8 u	27 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the persimmons is equal to 70% of the apples. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the persimmons = 7x110x1 of the apples
735 of the persimmons = 710 of the apples 

Persimmons : Apples
35 : 10 _(÷5)
7 : 2

The total number of persimmons and apples is repeated.  Make the total number of persimmons and apples the same.  LCM of 9 and 4 is 36.

Number of less apples than pomegranates
= 27 u - 8 u
= 19 u

19 u = 76

1 u = 76 ÷ 19 = 4

Number of the fruits in the box altogether
= 28 u + 8 u + 27 u
= 63 u
= 63 x 4
= 252

Answer(s): 252