A box contains some pears, mangosteens and chikoos. 0.4 of the pears is equal to 70% of the mangosteens. The number of chikoos is ²₃ of the total number of mangosteens and pears. If there are 80 less mangosteens than chikoos, how many fruits are there in the box altogether?

Pears	Mangosteens	Chikoos
7x3	4x3
3x11		2x11
21 u	12 u	22 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the pears is equal to 70% of the mangosteens. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the pears = 7x210x2 of the mangosteens
1435 of the pears = 1420 of the mangosteens 

Pears : Mangosteens
35 : 20 _(÷5)
7 : 4

The total number of pears and mangosteens is repeated.  Make the total number of pears and mangosteens the same.  LCM of 11 and 3 is 33.

Number of less mangosteens than chikoos
= 22 u - 12 u
= 10 u

10 u = 80

1 u = 80 ÷ 10 = 8

Number of the fruits in the box altogether
= 21 u + 12 u + 22 u
= 55 u
= 55 x 8
= 440

Answer(s): 440