A container contains some pomegranates, apples and kiwis. 0.6 of the pomegranates is equal to 80% of the apples. The number of kiwis is ⁵₆ of the total number of apples and pomegranates. If there are 102 less apples than kiwis, how many fruits are there in the container altogether?

Pomegranates	Apples	Kiwis
4x6	3x6
6x7		5x7
24 u	18 u	35 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the pomegranates is equal to 80% of the apples. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the pomegranates = 4x35x3 of the apples
1220 of the pomegranates = 1215 of the apples 

Pomegranates : Apples
20 : 15 _(÷5)
4 : 3

The total number of pomegranates and apples is repeated.  Make the total number of pomegranates and apples the same.  LCM of 7 and 6 is 42.

Number of less apples than kiwis
= 35 u - 18 u
= 17 u

17 u = 102

1 u = 102 ÷ 17 = 6

Number of the fruits in the container altogether
= 24 u + 18 u + 35 u
= 77 u
= 77 x 6
= 462

Answer(s): 462