A box contains some pomegranates, lemons and chikoos. 0.2 of the pomegranates is equal to 80% of the lemons. The number of chikoos is
23 of the total number of lemons and pomegranates. If there are 21 more chikoos than lemons, how many fruits are there in the box altogether?
Pomegranates |
Lemons |
Chikoos |
4x3 |
1x3 |
|
3x5 |
2x5 |
12 u |
3 u |
10 u |
0.2 =
210=
15 80% =
80100 =
45 0.2 of the pomegranates is equal to 80% of the lemons. Make the numerators the same. LCM of 1 and 4 is 4.
1x45x4 of the pomegranates =
4x15x1 of the lemons
420 of the pomegranates =
45 of the lemons
Pomegranates : Lemons
20 : 5
(÷5)
4 : 1
The total number of pomegranates and lemons is repeated. Make the total number of pomegranates and lemons the same. LCM of 5 and 3 is 15.
Number of more chikoos than lemons
= 10 u - 3 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of the fruits in the box altogether
= 12 u + 3 u + 10 u
= 25 u
= 25 x 3
= 75
Answer(s): 75