A box contains some mangoes, mangosteens and persimmons. 0.8 of the mangoes is equal to 70% of the mangosteens. The number of persimmons is ⁵₆ of the total number of mangosteens and mangoes. If there are 72 less mangosteens than persimmons, how many fruits are there in the box altogether?

Mangoes	Mangosteens	Persimmons
7x2	8x2
6x5		5x5
14 u	16 u	25 u

0.8 = ⁸₁₀= ⁴₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.8 of the mangoes is equal to 70% of the mangosteens. Make the numerators the same.  LCM of 4 and 7 is 28.

4x75x7 of the mangoes = 7x410x4 of the mangosteens
2835 of the mangoes = 2840 of the mangosteens 

Mangoes : Mangosteens
35 : 40 _(÷5)
7 : 8

The total number of mangoes and mangosteens is repeated.  Make the total number of mangoes and mangosteens the same.  LCM of 15 and 6 is 30.

Number of less mangosteens than persimmons
= 25 u - 16 u
= 9 u

9 u = 72

1 u = 72 ÷ 9 = 8

Number of the fruits in the box altogether
= 14 u + 16 u + 25 u
= 55 u
= 55 x 8
= 440

Answer(s): 440