A container contains some pears, pomegranates and mangoes. 0.6 of the pears is equal to 80% of the pomegranates. The number of mangoes is ²₃ of the total number of pomegranates and pears. If there are 55 more mangoes than pomegranates, how many fruits are there in the container altogether?

Pears	Pomegranates	Mangoes
4x3	3x3
3x7		2x7
12 u	9 u	14 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the pears is equal to 80% of the pomegranates. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the pears = 4x35x3 of the pomegranates
1220 of the pears = 1215 of the pomegranates 

Pears : Pomegranates
20 : 15 _(÷5)
4 : 3

The total number of pears and pomegranates is repeated.  Make the total number of pears and pomegranates the same.  LCM of 7 and 3 is 21.

Number of more mangoes than pomegranates
= 14 u - 9 u
= 5 u

5 u = 55

1 u = 55 ÷ 5 = 11

Number of the fruits in the container altogether
= 12 u + 9 u + 14 u
= 35 u
= 35 x 11
= 385

Answer(s): 385