A box contains some pears, kiwis and pomegranates. 0.6 of the pears is equal to 70% of the kiwis. The number of pomegranates is ⁴₅ of the total number of kiwis and pears. If there are 154 more pomegranates than kiwis, how many fruits are there in the box altogether?

Pears	Kiwis	Pomegranates
7x5	6x5
5x13		4x13
35 u	30 u	52 u

0.6 = ⁶₁₀= ³₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.6 of the pears is equal to 70% of the kiwis. Make the numerators the same.  LCM of 3 and 7 is 21.

3x75x7 of the pears = 7x310x3 of the kiwis
2135 of the pears = 2130 of the kiwis 

Pears : Kiwis
35 : 30 _(÷5)
7 : 6

The total number of pears and kiwis is repeated.  Make the total number of pears and kiwis the same.  LCM of 13 and 5 is 65.

Number of more pomegranates than kiwis
= 52 u - 30 u
= 22 u

22 u = 154

1 u = 154 ÷ 22 = 7

Number of the fruits in the box altogether
= 35 u + 30 u + 52 u
= 117 u
= 117 x 7
= 819

Answer(s): 819