A box contains some oranges, pears and pomegranates. 0.4 of the oranges is equal to 70% of the pears. The number of pomegranates is ⁵₈ of the total number of pears and oranges. If there are 92 more pomegranates than pears, how many fruits are there in the box altogether?

Oranges	Pears	Pomegranates
7x8	4x8
8x11		5x11
56 u	32 u	55 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the oranges is equal to 70% of the pears. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the oranges = 7x210x2 of the pears
1435 of the oranges = 1420 of the pears 

Oranges : Pears
35 : 20 _(÷5)
7 : 4

The total number of oranges and pears is repeated.  Make the total number of oranges and pears the same.  LCM of 11 and 8 is 88.

Number of more pomegranates than pears
= 55 u - 32 u
= 23 u

23 u = 92

1 u = 92 ÷ 23 = 4

Number of the fruits in the box altogether
= 56 u + 32 u + 55 u
= 143 u
= 143 x 4
= 572

Answer(s): 572