A container contains some pomegranates, pears and oranges. 0.8 of the pomegranates is equal to 60% of the pears. The number of oranges is ³₄ of the total number of pears and pomegranates. If there are 50 more oranges than pears, how many fruits are there in the container altogether?

Pomegranates	Pears	Oranges
3x4	4x4
4x7		3x7
12 u	16 u	21 u

0.8 = ⁸₁₀= ⁴₅
60% = ⁶⁰₁₀₀ = ³₅

0.8 of the pomegranates is equal to 60% of the pears. Make the numerators the same.  LCM of 4 and 3 is 12.

4x35x3 of the pomegranates = 3x45x4 of the pears
1215 of the pomegranates = 1220 of the pears 

Pomegranates : Pears
15 : 20 _(÷5)
3 : 4

The total number of pomegranates and pears is repeated.  Make the total number of pomegranates and pears the same.  LCM of 7 and 4 is 28.

Number of more oranges than pears
= 21 u - 16 u
= 5 u

5 u = 50

1 u = 50 ÷ 5 = 10

Number of the fruits in the container altogether
= 12 u + 16 u + 21 u
= 49 u
= 49 x 10
= 490

Answer(s): 490