A box contains some pears, mangosteens and chikoos. 0.6 of the pears is equal to 80% of the mangosteens. The number of chikoos is ²₃ of the total number of mangosteens and pears. If there are 10 less mangosteens than chikoos, how many fruits are there in the box altogether?

Pears	Mangosteens	Chikoos
4x3	3x3
3x7		2x7
12 u	9 u	14 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the pears is equal to 80% of the mangosteens. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the pears = 4x35x3 of the mangosteens
1220 of the pears = 1215 of the mangosteens 

Pears : Mangosteens
20 : 15 _(÷5)
4 : 3

The total number of pears and mangosteens is repeated.  Make the total number of pears and mangosteens the same.  LCM of 7 and 3 is 21.

Number of less mangosteens than chikoos
= 14 u - 9 u
= 5 u

5 u = 10

1 u = 10 ÷ 5 = 2

Number of the fruits in the box altogether
= 12 u + 9 u + 14 u
= 35 u
= 35 x 2
= 70

Answer(s): 70