A container contains some pears, apples and mangoes. 0.6 of the pears is equal to 70% of the apples. The number of mangoes is ³₅ of the total number of apples and pears. If there are 81 less apples than mangoes, how many fruits are there in the container altogether?

Pears	Apples	Mangoes
7x5	6x5
5x13		3x13
35 u	30 u	39 u

0.6 = ⁶₁₀= ³₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.6 of the pears is equal to 70% of the apples. Make the numerators the same.  LCM of 3 and 7 is 21.

3x75x7 of the pears = 7x310x3 of the apples
2135 of the pears = 2130 of the apples 

Pears : Apples
35 : 30 _(÷5)
7 : 6

The total number of pears and apples is repeated.  Make the total number of pears and apples the same.  LCM of 13 and 5 is 65.

Number of less apples than mangoes
= 39 u - 30 u
= 9 u

9 u = 81

1 u = 81 ÷ 9 = 9

Number of the fruits in the container altogether
= 35 u + 30 u + 39 u
= 104 u
= 104 x 9
= 936

Answer(s): 936