A box contains some mangosteens, kiwis and pears. 0.2 of the mangosteens is equal to 70% of the kiwis. The number of pears is ⁴₇ of the total number of kiwis and mangosteens. If there are 176 more pears than kiwis, how many fruits are there in the box altogether?

Mangosteens	Kiwis	Pears
7x7	2x7
7x9		4x9
49 u	14 u	36 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the mangosteens is equal to 70% of the kiwis. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the mangosteens = 7x110x1 of the kiwis
735 of the mangosteens = 710 of the kiwis 

Mangosteens : Kiwis
35 : 10 _(÷5)
7 : 2

The total number of mangosteens and kiwis is repeated.  Make the total number of mangosteens and kiwis the same.  LCM of 9 and 7 is 63.

Number of more pears than kiwis
= 36 u - 14 u
= 22 u

22 u = 176

1 u = 176 ÷ 22 = 8

Number of the fruits in the box altogether
= 49 u + 14 u + 36 u
= 99 u
= 99 x 8
= 792

Answer(s): 792