A container contains some pears, oranges and chikoos. 0.4 of the pears is equal to 30% of the oranges. The number of chikoos is ⁵₈ of the total number of oranges and pears. If there are 27 less oranges than chikoos, how many fruits are there in the container altogether?

Pears	Oranges	Chikoos
3x8	4x8
8x7		5x7
24 u	32 u	35 u

0.4 = ⁴₁₀= ²₅
30% = ³⁰₁₀₀ = ³₁₀

0.4 of the pears is equal to 30% of the oranges. Make the numerators the same.  LCM of 2 and 3 is 6.

2x35x3 of the pears = 3x210x2 of the oranges
615 of the pears = 620 of the oranges 

Pears : Oranges
15 : 20 _(÷5)
3 : 4

The total number of pears and oranges is repeated.  Make the total number of pears and oranges the same.  LCM of 7 and 8 is 56.

Number of less oranges than chikoos
= 35 u - 32 u
= 3 u

3 u = 27

1 u = 27 ÷ 3 = 9

Number of the fruits in the container altogether
= 24 u + 32 u + 35 u
= 91 u
= 91 x 9
= 819

Answer(s): 819