A container contains some chikoos, kiwis and oranges. 0.4 of the chikoos is equal to 70% of the kiwis. The number of oranges is ⁵₆ of the total number of kiwis and chikoos. If there are 62 more oranges than kiwis, how many fruits are there in the container altogether?

Chikoos	Kiwis	Oranges
7x6	4x6
6x11		5x11
42 u	24 u	55 u

0.4 = ⁴₁₀= ²₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.4 of the chikoos is equal to 70% of the kiwis. Make the numerators the same.  LCM of 2 and 7 is 14.

2x75x7 of the chikoos = 7x210x2 of the kiwis
1435 of the chikoos = 1420 of the kiwis 

Chikoos : Kiwis
35 : 20 _(÷5)
7 : 4

The total number of chikoos and kiwis is repeated.  Make the total number of chikoos and kiwis the same.  LCM of 11 and 6 is 66.

Number of more oranges than kiwis
= 55 u - 24 u
= 31 u

31 u = 62

1 u = 62 ÷ 31 = 2

Number of the fruits in the container altogether
= 42 u + 24 u + 55 u
= 121 u
= 121 x 2
= 242

Answer(s): 242