A container contains some kiwis, passion fruits and persimmons. 0.4 of the kiwis is equal to 80% of the passion fruits. The number of persimmons is ⁴₅ of the total number of passion fruits and kiwis. If there are 21 less passion fruits than persimmons, how many fruits are there in the container altogether?

Kiwis	Passion Fruits	Persimmons
2x5	1x5
5x3		4x3
10 u	5 u	12 u

0.4 = ⁴₁₀= ²₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.4 of the kiwis is equal to 80% of the passion fruits. Make the numerators the same.  LCM of 2 and 4 is 4.

2x25x2 of the kiwis = 4x15x1 of the passion fruits
410 of the kiwis = 45 of the passion fruits 

Kiwis : Passion Fruits
10 : 5 _(÷5)
2 : 1

The total number of kiwis and passion fruits is repeated.  Make the total number of kiwis and passion fruits the same.  LCM of 3 and 5 is 15.

Number of less passion fruits than persimmons
= 12 u - 5 u
= 7 u

7 u = 21

1 u = 21 ÷ 7 = 3

Number of the fruits in the container altogether
= 10 u + 5 u + 12 u
= 27 u
= 27 x 3
= 81

Answer(s): 81